CHCl3/MeOH/ H2O
= 0.5:1: 0.4 CHCl3/MeOH/ H2O
= 1: 1: 0.4 CHCl3/MeOH/ H2O
= 1: 1: 0.9
1) add 1.5 ml of
CHCl3/MeOH (1:2) to a tissue sample in 0.4 ml of
buffer and vortex vigorously
2) add 0.5 ml of CHCl3 and
vortex
3) add 0.5 ml of H2O and
vortex
4) centrifuge briefly at 3000 rpm to
separate phases (a white precipitate will appear at the
interface)
5) transfer the organic (lower) layer
to a new tube and concentrate by speed vac.
*If acidic lipids are to be extracted, add 0.5 ml of 1% HClO4 instead of 0.5 ml of H2O.
Also, the volumes in the above procedure may be modified but it is necessary to always keep the ratios of CHCl3/MeOH/ H2O as listed.
reference: Canadian J. Biochem. 37: 911-917, 1959